C:带有const修饰的指针解读

来源:岁月联盟 编辑:猪蛋儿 时间:2012-05-19

通过实例来看看const所修饰的指针使用方法:

 1、

  先看一个普通的指针使用。

  形式:int *pTmp

  含义:一个普通的指向int类型的指针


[cpp]
int main(int argc, char *argv[]) 

  int i = 1; 
   
  int  *pTmp = &i;  
  printf("pTmp = %d/n", *pTmp); 
   
  i = 2; 
  printf("pTmp = %d/n", *pTmp); 
   
  (*pTmp)++;  
  printf("pTmp = %d/n", *pTmp); 
   
  system("PAUSE"); 
   
  return 0; 

int main(int argc, char *argv[])
{
  int i = 1;
 
  int  *pTmp = &i;
  printf("pTmp = %d/n", *pTmp);
 
  i = 2;
  printf("pTmp = %d/n", *pTmp);
 
  (*pTmp)++;
  printf("pTmp = %d/n", *pTmp);
 
  system("PAUSE");
 
  return 0;
}

  输出:


[plain]
pTmp = 1 
pTmp = 2 
pTmp = 3 
请按任意键继续. . . 
pTmp = 1
pTmp = 2
pTmp = 3
请按任意键继续. . .
 没有任何问题,pTmp指针你可以任意操作。

2、

形式:const int *pTmp

含义:表示pTmp所指向的对象是只读的,但pTmp可指向其他地址,即pTmp可变。


[cpp]
int main(int argc, char *argv[]) 

  int i = 1; 
  int j = 100; 
   
  const int  *pTmp = &i; /*正确:表示pTmp所指向的对象是只读的,但pTmp可指向其他地址,即pTmp可变*/  
  printf("pTmp = %d/n", *pTmp); 
   
  i = 2; 
  printf("pTmp = %d/n", *pTmp); 
   
  pTmp = &j;            /*正确:将pTmp指向变量j的地址*/ 
  printf("pTmp = %d/n", *pTmp); 
   
   
  (*pTmp)++; /*错误,pTmp指向的对象是只读的,编译出错提示:assignment of read-only location */ 
  printf("pTmp = %d/n", *pTmp); 
   
  system("PAUSE"); 
   
  return 0; 

int main(int argc, char *argv[])
{
  int i = 1;
  int j = 100;
 
  const int  *pTmp = &i; /*正确:表示pTmp所指向的对象是只读的,但pTmp可指向其他地址,即pTmp可变*/
  printf("pTmp = %d/n", *pTmp);
 
  i = 2;
  printf("pTmp = %d/n", *pTmp);
 
  pTmp = &j;            /*正确:将pTmp指向变量j的地址*/
  printf("pTmp = %d/n", *pTmp);
 
 
  (*pTmp)++; /*错误,pTmp指向的对象是只读的,编译出错提示:assignment of read-only location */
  printf("pTmp = %d/n", *pTmp);
 
  system("PAUSE");
 
  return 0;
}
3、


形式:int const *pTmp

含义:与2相同, 表示pTmp所指向的对象是只读的,但pTmp可指向其他地址,即pTmp可变。


[cpp]
int main(int argc, char *argv[]) 

  int i = 1; 
  int j = 100; 
   
  const int  *pTmp = &i; /*正确:表示pTmp所指向的对象是只读的,但pTmp可指向其他地址,即pTmp可变*/  
  printf("pTmp = %d/n", *pTmp); 
   
  i = 2; 
  printf("pTmp = %d/n", *pTmp); 
   
  pTmp = &j;            /*正确:将pTmp指向变量j的地址*/ 
  printf("pTmp = %d/n", *pTmp); 
   
   
  (*pTmp)++; /*错误,pTmp指向的对象是只读的,编译出错提示:assignment of read-only location */ 
  printf("pTmp = %d/n", *pTmp); 
   
  system("PAUSE");   
   
  return 0; 

int main(int argc, char *argv[])
{
  int i = 1;
  int j = 100;
 
  const int  *pTmp = &i; /*正确:表示pTmp所指向的对象是只读的,但pTmp可指向其他地址,即pTmp可变*/
  printf("pTmp = %d/n", *pTmp);
 
  i = 2;
  printf("pTmp = %d/n", *pTmp);
 
  pTmp = &j;            /*正确:将pTmp指向变量j的地址*/
  printf("pTmp = %d/n", *pTmp);
 
 
  (*pTmp)++; /*错误,pTmp指向的对象是只读的,编译出错提示:assignment of read-only location */
  printf("pTmp = %d/n", *pTmp);
 
  system("PAUSE"); 
 
  return 0;
}
4、

形式:int * const pTmp

含义:pTmp不可修改,但pTmp所指向的对象可以修改。


[cpp]
int main(int argc, char *argv[]) 

  int i = 1; 
  int j = 100; 
   
  int * const pTmp = &i;  
  printf("pTmp = %d/n", *pTmp); 
   
  i = 2; 
  printf("pTmp = %d/n", *pTmp); 
   
  pTmp = &j;  /*错误,pTmp不可修改,编译提示:error:assignment of read-only variable `pTmp'*/ 
  printf("pTmp = %d/n", *pTmp); 
   
   
  (*pTmp)++; /*正确,pTmp所指向的对象可以修改 */ 
  printf("pTmp = %d/n", *pTmp); 
   
  system("PAUSE");   
   
  return 0; 

int main(int argc, char *argv[])
{
  int i = 1;
  int j = 100;
 
  int * const pTmp = &i;
  printf("pTmp = %d/n", *pTmp);
 
  i = 2;
  printf("pTmp = %d/n", *pTmp);
 
  pTmp = &j;  /*错误,pTmp不可修改,编译提示:error:assignment of read-only variable `pTmp'*/
  printf("pTmp = %d/n", *pTmp);
 
 
  (*pTmp)++; /*正确,pTmp所指向的对象可以修改 */
  printf("pTmp = %d/n", *pTmp);
 
  system("PAUSE"); 
 
  return 0;
}
5、

 形式:const int * const pTmp

 含义:pTmp不可修改,pTmp所指对象也不能修改。


[cpp]
int main(int argc, char *argv[]) 

  int i = 1; 
  int j = 100; 
   
  const int * const pTmp = &i;  
  printf("pTmp = %d/n", *pTmp); 
   
  i = 2;  /*正确*/ 
  printf("pTmp = %d/n", *pTmp); 
   
  pTmp = &j;  /*错误:error: assignment of read-only variable `pTmp'*/ 
  printf("pTmp = %d/n", *pTmp); 
   
   
  (*pTmp)++;  /*错误:error: increment of read-only location*/ 
  printf("pTmp = %d/n", *pTmp); 
   
  system("PAUSE"); 
   
  return 0; 

   

 

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